A 2.0 kg ball moving east at 0.5 m/s collides with a 3.0 kg ball moving west at 0.75 m/s. After the collision, the lighter ball moves west at 0.65 m/s. What is the velocity of the larger ball after the collision?
m1v1−m2v2=−m1v1′+m2v2′→m_1v_1-m_2v_2=-m_1v_1'+m_2v_2'\tom1v1−m2v2=−m1v1′+m2v2′→
v2′=(m1v1−m2v2+m1v1′)/m2=v_2'=(m_1v_1-m_2v_2+m_1v_1')/m_2=v2′=(m1v1−m2v2+m1v1′)/m2=
=(2⋅0.5−3⋅0.75+2⋅0.65)/3=0.017 (m/s)=(2\cdot0.5-3\cdot0.75+2\cdot0.65)/3=0.017\ (m/s)=(2⋅0.5−3⋅0.75+2⋅0.65)/3=0.017 (m/s) eastward
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