Answer to Question #279528 in Physics for Kaikai

Question

In the endothermic process the volume of a gas contracted from 180 ml to 175ml against a constant pressure of 722 during the process 30 cal of heat energy were given off what was the internal energy change for the system in joules

Answer 1

$30\ cal=125.52\ J$

$Q=\Delta U+p\Delta V \to \Delta U=Q-p\Delta V=$

$=-125.52+722000\cdot0.000005=-121.91\ (J)$ . Answer