In the endothermic process the volume of a gas contracted from 180 ml to 175ml against a constant pressure of 722 during the process 30 cal of heat energy were given off what was the internal energy change for the system in joules
30 cal=125.52 J30\ cal=125.52\ J30 cal=125.52 J
Q=ΔU+pΔV→ΔU=Q−pΔV=Q=\Delta U+p\Delta V \to \Delta U=Q-p\Delta V=Q=ΔU+pΔV→ΔU=Q−pΔV=
=−125.52+722000⋅0.000005=−121.91 (J)=-125.52+722000\cdot0.000005=-121.91\ (J)=−125.52+722000⋅0.000005=−121.91 (J) . Answer
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