A 15kg box is being pulled with a force of 60N and is sliding with an acceleration of 4 m/s^2. Find the coefficient of kinetic friction.
F=ma→60−μmg=ma→μ=(60−ma)/(mg)=F=ma\to 60-\mu mg=ma\to \mu=(60-ma)/(mg)=F=ma→60−μmg=ma→μ=(60−ma)/(mg)=
=(60−15⋅4)/(15⋅9.8)=0=(60-15\cdot 4)/(15\cdot9.8)=0=(60−15⋅4)/(15⋅9.8)=0 . Answer
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