Question

A heat engine takes in 1500 J of heat at 2000 K and rejects 950 J of heat at 1000 K. Find the (a)   maximum efficiency of this engine and (b) its actual efficiency.

Answer 1

(a) $\eta=(T_1-T_2)/T_1=(2000-1000)/2000=0.5$

(b) $\eta=(Q_1-Q_2)/Q_1=(1500-950)/1500=0.37$