Answer to Question #278467 in Physics for Nnnnmmmm

Question

The equation of a transverse sinusoidal wave is given by: y = 2x10^-3 sin (18x - 600t +30⁰) m. Find the:

(a) amplitude of the wave

(b) the wavelength

(c) the frequency

(d) the wave speed, and

(e) the displacement at position 0m and time 0s

(f) the maximum transverse particle speed.​

Answer 1

(a) $A=0.002\ (m)$

(b) $\lambda=2\pi/k=2\cdot3.14/18=0.35\ (m)$

(c) $\nu=\omega/(2\pi)=600/(2\cdot3.14)=95.5\ (Hz)$

(d) $v=\omega/k=600/18=33.3\ (m/s)$

(e) $y=0.002\cdot\sin(0-0+30)=0.001\ (m)$

(f) $v_{max}=A\omega=0.002\cdot600=1.2\ (m/s)$