Question

The space shuttle releases a satellite into a circular orbit 630 km

km above the Earth.

How fast must the shuttle be moving (relative to Earth's center) when the release occurs?

Answer 1

$$v=\sqrt{(6.67\cdot10^{-11})\frac{(5.97\cdot10^{24})}{((630+6371)\cdot10^{3})}}\\v=7542\frac{m}{s}$$