A long jumper moving horizontally with a speed of 5.3 m/s has a kinetic energy of 235 J. Calculate the mass of the jumper.
KE=mv2/2→m=2KE/v2=2⋅235/5.32=16.7 (kg)KE=mv^2/2\to m=2KE/v^2=2\cdot235/5.3^2=16.7\ (kg)KE=mv2/2→m=2KE/v2=2⋅235/5.32=16.7 (kg) . Answer
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