Question

An 8.00-𝑘𝑔 point mass and a 12.0-𝑘𝑔 point mass are held in place 50.0 𝑐𝑚 apart. A particle of mass 𝑚 is released from a point between the two masses 20.0 𝑐𝑚 from the 8.00-𝑘𝑔 mass along the line connecting the two fixed masses. Find the magnitude and direction of the acceleration of the particle. 

Answer 1

$$a=(6.67\cdot10^{-11})\frac{8}{0.2^2}-(6.67\cdot10^{-11})\frac{12}{0.3^2}\\a=4.45\cdot10^{-9}\frac{m}{s^2}$$

To the 8.00-𝑘𝑔 point mass.