What speed would a 2,000-ππ sport utility vehicle have to attain in order to have π) the same momentum? ππ) the same kinetic energy?
Suppose that the momentum is "p" and the kinetic energy is "E" . So,
"p=mv\\to v=p\/m=p\/2000" .
"E=mv^2\/2\\to v=\\sqrt{2E\/m}=\\sqrt{2E\/2000}=\\sqrt{E\/1000}" .
Comments
Leave a comment