What is the magnitude of the momentum of a 10,000-𝑘𝑔 truck whose speed is 12.0 𝑚/𝑠?
mv=10000⋅12=120 000 (kg⋅m/s)mv=10000\cdot12=120\ 000\ (kg\cdot m/s)mv=10000⋅12=120 000 (kg⋅m/s) . Answer
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