Answer to Question #276689 in Physics for Yisfa

Question #276689

find the range of aprojectile launched at an angle of 45° when an intial velocity of 25m/s.

Expert's answer

"l=\\frac{v_0^2\\sin2\\alpha}{2g}=\\frac{25^2\\cdot\\sin(2\\cdot45\u00b0)}{2\\cdot9.8}\\approx32\\ (m)" . Answer

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