Question #276617

What must be the radius of a star of mass 2 x 10^30 kg so that the escape speed from this star is equal to 2 x 10^8 m/s?


1
Expert's answer
2021-12-20T10:26:50-0500

The radius is


r=2GMv2=6673 m.r=\frac{2GM}{v^2}=6673\text{ m}.


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