Question #276615

The moon has a mass of 7.35 x 10^22 kg and a radius of 1.738 x 10^6 m. At what speed must a rocket be launched from the moon's surface so as not to fall back to moon.


1
Expert's answer
2021-12-20T10:26:54-0500

We can find the escape velocity of the rocket as follows:


v=2GMr,v=\sqrt{\dfrac{2GM}{r}},v=2×6.67×1011 N×m2kg2×7.35×1022 kg1.738×106 m,v=\sqrt{\dfrac{2\times6.67\times10^{-11}\ \dfrac{N\times m^2}{kg^2}\times7.35\times10^{22}\ kg}{1.738\times10^6\ m}},v=2380 ms=2.38 kms.v=2380\ \dfrac{m}{s}=2.38\ \dfrac{km}{s}.

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