Question

A boy throws a stone straight upward with an initial velocity of 5 m/s from the surface of the Earth. What is the maximum height above the starting point will the stone reach before it starts falling back?

Answer 1

$h=\frac{v^2-v_0^2}{2g}=\frac{0-5^2}{2\cdot(-9.8)}=1.28\ (m)$ . Answer