Answer to Question #276600 in Physics for Unknown357973

Question

A supersonic bomber which had a momentum of 8,800,000 kg-m/s east, comes to a halt on the ground. What impulse is applied?

Answer 1

The impulse is the change in momentum:

$$I=\Delta p=p_f-p_i=0-8800000=\\\space\\=-8800000\text{ kg}·\text{m/s}.$$