Answer to Question #276600 in Physics for Unknown357973

Question #276600

A supersonic bomber which had a momentum of 8,800,000 kg-m/s east, comes to a halt on the ground. What impulse is applied?

Expert's answer

The impulse is the change in momentum:

"I=\\Delta p=p_f-p_i=0-8800000=\\\\\\space\\\\=-8800000\\text{ kg}\u00b7\\text{m\/s}."

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