Question

Three 20-Ω resistors are connected in series to a 6-V battery that has only negligible internal resistance. What is the voltage difference across each resistor in V? (Hint: First calculate the current going through the three resistors and then find the voltage difference.)

Answer 1

$R=R_1+R_2+R_3=20+20+20=60\ (\Omega)$

$I=V/R=6/60=0.1\ (A)$

$V_1=V_2=V_3=I\cdot R_1=0.1\cdot20=2\ (V)$ . Answer