Question #276546

Assume T=kL^x g^y. Find the value of x and y for which the above equation is dimensionally correct

1
Expert's answer
2021-12-07T09:51:58-0500
T=Lx(LT2)y1=2yy=0.5x=y=0.5T=L^x(LT^{-2})^y\\1=-2y\\y=-0.5\\x=-y=0.5


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