Question #276495

A capillary tube with an inside radius of 638 π‘›π‘š can support a 100 π‘šπ‘š column of

liquid that has a density of 820 π‘˜π‘”π‘š-3. The observed contact angle is 12.5Β°. Find

the surface tension of the liquid for β„Ž = 20 π‘π‘š



Expert's answer

According to the Jurin's law


h=2Οƒ(Οβˆ’Ο0)grβ‹…cos⁑θ→σ=h(Οβˆ’Ο0)gr/(2cos⁑θ)=h=\frac{2\sigma}{(\rho-\rho_0)gr}\cdot\cos\theta\to \sigma=h(\rho-\rho_0)gr/(2\cos\theta)=


=0.2β‹…(820βˆ’1.29)β‹…9.8β‹…638β‹…10βˆ’9/(2β‹…cos⁑12.5Β°)=5.24β‹…10βˆ’4 (N/m)=0.2\cdot(820-1.29)\cdot9.8\cdot638\cdot10^{-9}/(2\cdot\cos12.5Β°)=5.24\cdot10^{-4} \ (N/m) . Answer

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