Question

What is the horizontal displacement of the object thrown into the air at a velocity of 30 m/s with an angle of 28 degree?

Answer 1

Given:

$v_0=30\:\rm m/s$

$\theta=28^\circ$

The range of projectile

$$R=\frac{v_0^2\sin2\theta}{g}=\frac{30^2\sin56^\circ}{9.8}=76\: \rm m$$