Question

The radius of a silver bar is 30 𝑐𝑚. What force is required to stretch the bar by

12.7% of its length where Young’s modulus is 𝑌 = 7.25 × 1010 𝑁𝑚−2

Answer 1

$$7.25\cdot10^{10}=\frac{F}{\pi(0.3)^20.127}\\F=2.60\cdot10^{9}\ N$$