A capillary tube with an inside radius of 638 ππ can support a 100 ππ column of
liquid that has a density of 820 πππβ3. The observed contact angle is 12.5Β°. Find
the surface tension of the liquid for β = 20 ππ. need to solution
According to the Jurin'sΒ law
"h=\\frac{2\\sigma}{(\\rho-\\rho_0)gr}\\cdot\\cos\\theta\\to \\sigma=h(\\rho-\\rho_0)gr\/(2\\cos\\theta)="
"=0.2\\cdot(820-1.29)\\cdot9.8\\cdot638\\cdot10^{-9}\/(2\\cdot\\cos12.5\u00b0)=5.24\\cdot10^{-4} \\ (N\/m)" . Answer
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