Answer to Question #275866 in Physics for sajidur

Question

If 12𝑁 force is applied to a fluid of cross-section 5.34 𝑐𝑚2 with a shearing rate of 0.7 𝑠 −1 then find the viscosity of the fluid.

Answer 1

The viscosity is

$$\mu=F/(Ar)=\frac{12}{(5.34·10^{-4})(0.7)}=32103\text{ Pa}·\text{s}.$$