Answer to Question #275861 in Physics for sajidur

Question #275861

The radius of a silver bar is 30 𝑐𝑚. What force is required to stretch the bar by 12.7% of its length where Young’s modulus is 𝑌 = 7.25 × 1010 𝑁𝑚−2 .


1
Expert's answer
2021-12-06T09:47:35-0500

The strain of 12.7%, or 0.127, is what we will use to solve the problem:


ϵ=σE=FAE, F=ϵAE=ϵπr2E, F=2.6 MN.\epsilon=\frac{\sigma}{E}=\frac{F}{AE},\\\space\\ F=\epsilon AE=\epsilon·\pi r^2·E,\\\space\\ F=2.6\text{ MN}.


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