Question #275406

How long will it take a 250-N box initially at rest reach a speed of 36 km/h when a force of 65 N is applied on it? The floor is frictionless.




O 1.2 S




O not among the choices




O 2.3 s




O 4.5 s




O 3.9 S

1
Expert's answer
2021-12-06T09:44:46-0500

Given:

W=250NW=250\:\rm N

F=65NF=65\:\rm N

Δv=36km/h=10m/s\Delta v=36\:\rm km/h=10\: m/s

Δt?\Delta t-?


The Newton's second law says

ma=Fma=F

Hence, the acceleration of the object

a=Fm=gFW=9.865250=2.55m/s2a=\frac{F}{m}=g\frac{F}{W}=\rm 9.8*\frac{65}{250}=2.55\: m/s^2

The time of movement

Δt=Δva=102.55=3.9s\Delta t=\frac{\Delta v}{a}=\frac{10}{2.55}=3.9\:\rm s

Answer: 3.9s3.9\:\rm s


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