Answer to Question #275245 in Physics for Zen

Question

A 700.0-N sign hangs from the end of a uniform strut. The strut is 4.0 m long and weighs

800.0 N. The strut is supported by a hinge at the wall and by a cable whose other end is tied

to the wall at a point 3.0 m above the left end of the strut. Find the tension in the supporting

cable and the force of the hinge on the strut.

Answer 1

The tension in the supporting cable

$\sum\tau_B=0\to800\cdot2+700\cdot4-4T\cdot(3/5)=0\to T=1833\ (N)$ . Answer

The force of the hinge on the strut.

$F_h=T\cdot(4/5)=1833\cdot(4/5)=1467\ (N)$

$\sum\tau_A =0\to800\cdot2-F_v\cdot4=0\to F_v=400\ (N)$

$F=\sqrt{1467^+400^2}=1521\ (N)$ . Answer