Question #275110

1. A cat is moving at 18 m/s when it accelerates at 4 m/s^2 for 2 seconds. What is his new velocity?

2.A car slows from 22 m/s to 3.0 m/s at a constant rate of 2.1 m/s^2. How many seconds are required before the car is traveling 3.0 m/s?

3. A race car is traveling at +76 m/s when it slows down at -9 m/s^2 for 4 seconds. What is his new velocity?

4. A speedboat increases in speed uniformly from 20 m/s to 30 m/s in a distance of 200 m.   What is the acceleration of the speedboat?

5. Julie is walking around a track at a 2 m/s for some exercise. She then decides to start jogging so she accelerates at a rate of 0.5 m/s^2 for 3 seconds. How far did Julie travel from the time she started to accelerate to the end of the 3 seconds?



1
Expert's answer
2021-12-03T12:43:50-0500

1)

v=v0+at,v=v_0+at,v=18 ms+4 ms2×2 s=26 ms.v=18\ \dfrac{m}{s}+4\ \dfrac{m}{s^2}\times2\ s=26\ \dfrac{m}{s}.

2)

v=v0+at,v=v_0+at,t=vv0a=3 ms22 ms2.1 ms2=9.05 s.t=\dfrac{v-v_0}{a}=\dfrac{3\ \dfrac{m}{s}-22\ \dfrac{m}{s}}{-2.1\ \dfrac{m}{s^2}}=9.05\ s.

3)

v=v0+at,v=v_0+at,v=76 ms+(9 ms2)×4 s=40 ms.v=76\ \dfrac{m}{s}+(-9\ \dfrac{m}{s^2})\times4\ s=40\ \dfrac{m}{s}.

4)

v2=v02+2ad,v^2=v_0^2+2ad,a=v2v022d=(30 ms)2(20 ms)22×200 m=1.25 ms2.a=\dfrac{v^2-v_0^2}{2d}=\dfrac{(30\ \dfrac{m}{s})^2-(20\ \dfrac{m}{s})^2}{2\times200\ m}=1.25\ \dfrac{m}{s^2}.

5)

d=v0t+12at2,d=v_0t+\dfrac{1}{2}at^2,d=2 ms×3 s+12×0.5 ms2×(3 s)2=8.25 m.d=2\ \dfrac{m}{s}\times3\ s+\dfrac{1}{2}\times0.5\ \dfrac{m}{s^2}\times(3\ s)^2=8.25\ m.

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS