Question

A 980 kg test car travwls around a circular track with a radius of 625 meters. If the magnitude of the centripetal force is 2433 N, what is the car's speed in m/s. What is the car's centripetal acceleration.

Answer 1

The centripetal acceleration is

$$a=F/m=2433/980=2.48\text{ m/s}^2.$$

The speed:

$$v=\sqrt{ar}=39\text{ m/s}.$$