Answer to Question #274952 in Physics for Dhea

Question

A simple pendulum of length 30cm us suspended vertically. What is the period of the pendulum? What is the angular frequency of motion

Answer 1

The period of the simple pendulum is given as follows:

$$T = 2\pi \sqrt{\dfrac{L}{g}}$$

where $L = 30cm = 0.3m$ is its length, and $g = 9.8m/s^2$ is the gravitational acceleration.

Thus, obtain:

$$T = 2\pi \sqrt{\dfrac{0.3m}{9.8m/s^2}} \approx 1.1s$$

The angular frequency is:

$$\omega =\sqrt{\dfrac{g}{L}} = \sqrt{\dfrac{9.8}{0.3}} \approx 5.7rad/s$$

Answer. Period: 1.1s. angular frequency: 5.7 rad/s.