Answer to Question #274939 in Physics for Dhea

Question

A steel bar has a diameter of 1 cm with an original length of 2m. The bar is pulled by force of 365 N. Modulus of elasticity of steel is 2.1 times 10 to the power of eleven Pa. Determine change in length of the bar, the stress and strain experienced by the bar.

Answer 1

The strain:

$$\epsilon=\frac{\sigma}{E}=\frac{F}{AE}=2.21·10^{-5}.$$

Change in length:

$$\Delta L=\epsilon L=0.044\text{ mm}.$$

The stress:

$$\sigma=\epsilon E=4.647·10^6\text{ Pa}.$$