Question

In a seesaw, the person on the left weighs 900N and the person on the right weighs 400 N . If the person on the right is sitting 3 m from the fulcrum and the seesaw is balances, how far must the person on the left be from the fulcrum?

Answer 1

$$F_1x_1=F_2x_2\\900x=400(3)\\x=1.33\ m$$