Question

A particle is displaced 60 cm to the north and then is given a second displacement of 90 cm directly to the east. What is the average velocity of the particle if it covers the entire displacement within 2.15 seconds?

Answer 1

The displacement

$d=\sqrt{0.9^2+0.6^2}=1.08\ (m)$

The average velocity

$v=d/t=1.08/2.15=0.5\ (m/s)$ . Answer