Question #274561

A simple pendulum is found to vibrate 50 times within 200s. When 1.5m of its length is reduced to a certain length, it vibrates 50 times in 175s. Find the original length of the pendulum.

1
Expert's answer
2021-12-02T10:03:35-0500

For the original length, we have:


ToNo=2πlg, l=g(To2πNo)2=3.97 s.\frac{T_o}{N_o}=2\pi\sqrt{\frac{l}{g}},\\\space\\ l=g\bigg(\frac{T_o}{2\pi N_o}\bigg)^2=3.97\text{ s}.


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