Question #274388

What is the acceleration of a 45kg block at rest pushed by a 280N horizontal force up to 30degree inclined planw with a roughness coefficient of 0.15


1
Expert's answer
2021-12-02T10:04:32-0500


1) Determine the normal force:


N=mgcosθ+Fsinθ.N=mg\cos\theta+F\sin\theta.

2) The force of friction:


f=μN=μ(mgcosθ+Fsinθ).f=\mu N=\mu(mg\cos\theta+F\sin\theta).

3) The net force:


Fnet=Fcosθf, Fnet=Fcosθμ(mgcosθ+Fsinθ)=164 N.F_\text{net}=F\cos\theta-f,\\\space\\ F_\text{net}=F\cos\theta-\mu(mg\cos\theta+F\sin\theta)=164\text{ N}.

4) Calculate the acceleration:

a=Fnet/m=3.64 m/s2.a=F_\text{net}/m=3.64\text{ m/s}^2.


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