Question #273638

A particle moving along the x-axis in simple harmonic motion starts from the equilibrium position, the origin, at time t=0 and moves to the right. The position of the particle after time, t, is given by the following equation: x=2.0 sin 3πt m



Calculate:



A) the maximum velocity of the motion



B) the acceptation of the object after 2 seconds



C) the distance traveled by the particle from t=0s to t=2s

1
Expert's answer
2021-11-30T17:44:25-0500

a)


V=2(3π)=18.8msV=2(3\pi)=18.8\frac{m}{s}

b)


a=2(3π)2sin3(2)π=0ms2a=-2(3\pi)^2\sin 3(2)π=0\frac{m}{s^2}

c)


X=0 mX=0\ m


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