Answer to Question #273555 in Physics for Venus

Question

A crate is moving 2m along horizontal floor at a constant speed by a force of 50N which makes an angle of 30° above the horizontal. How much work is done on the crate by the force? Show complete solution.

Answer 1

By the definition of the work done, we have:

$$W=Fdcos\theta=50\ N\times2\ m\times cos30^{\circ}=86.6\ J.$$