Question #273555

A crate is moving 2m along horizontal floor at a constant speed by a force of 50N which makes an angle of 30° above the horizontal. How much work is done on the crate by the force? Show complete solution.

1
Expert's answer
2021-12-01T10:29:45-0500

By the definition of the work done, we have:


W=Fdcosθ=50 N×2 m×cos30=86.6 J.W=Fdcos\theta=50\ N\times2\ m\times cos30^{\circ}=86.6\ J.

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