Answer to Question #273553 in Physics for grey tyrant

Question

A basketball is shot through the air, hitting the backboard of a hoop. During the shot, the basketball was travelling at 8 m/s, and right after hitting the backboard, the basketball travels 1 m/s in the opposite direction. The mass of a standard basketball is 590g.

a. Find the kinetic energy of the basketball before hitting the backboard (2pts)

b. Find the kinetic energy of the basketball after hitting the backboard (2pts)

c. Find the work done by the backboard to the basketball (2pts)

Answer 1

(a)

$$KE_i=\dfrac{1}{2}mv_i^2,$$ $$KE_i=\dfrac{1}{2}\times0.59\ kg\times(8\ \dfrac{m}{s})^2=18.88\ J.$$

(b)

$$KE_f=\dfrac{1}{2}mv_f^2,$$ $$KE_f=\dfrac{1}{2}\times0.59\ kg\times(1\ \dfrac{m}{s})^2=0.295\ J.$$

(c)

$$W=\Delta KE=KE_f-KE_i,$$ $$W=0.295\ J-18.88\ J=-18.585\ J.$$