Answer to Question #273154 in Physics for jopay

Question #273154

The motor is used in lifting a 200 kg object at a constant speed of 3 cm/s. What power is being developed by the motor?

 


1
Expert's answer
2021-11-29T11:40:10-0500

By the definition of the power, we have:


P=Wt=Fht=Fv=mgv,P=\dfrac{W}{t}=\dfrac{Fh}{t}=Fv=mgv,P=200 kg×9.8 ms2×3 cms×1 m100 cm=58.8 W.P=200\ kg\times9.8\ \dfrac{m}{s^2}\times3\ \dfrac{cm}{s}\times\dfrac{1\ m}{100\ cm}=58.8\ W.

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