Answer to Question #273154 in Physics for jopay

Question

The motor is used in lifting a 200 kg object at a constant speed of 3 cm/s. What power is being developed by the motor?

 

Answer 1

By the definition of the power, we have:

$$P=\dfrac{W}{t}=\dfrac{Fh}{t}=Fv=mgv,$$ $$P=200\ kg\times9.8\ \dfrac{m}{s^2}\times3\ \dfrac{cm}{s}\times\dfrac{1\ m}{100\ cm}=58.8\ W.$$