To sterilize a 50.0-g glass babby bottle, we must raise its temperature from 22.0 degree celcius to 95.0 degree celcius . How much heat transfer is required?
Q=cm(t2−t1)=600⋅0.05⋅(95−22)=2190 (J)Q=cm(t_2-t_1)=600\cdot 0.05\cdot(95-22)=2190\ (J)Q=cm(t2−t1)=600⋅0.05⋅(95−22)=2190 (J) . Answer
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