Answer to Question #272858 in Physics for Manha

Question

An aeroplane takes off at an angle of 60 degree to the horizontal if the components of the velocity along the horizontal is 200 m/s what is the actual velocity? Also find the vertical components of its velocity

Answer 1

$v_x=v\cdot\cos60°\to v=v_x/\cos60°=200/\cos60°=$

$=400\ (m/s)$

$v_y=v\cdot\sin60°=400\cdot\sin60°=346\ (m/s)$