Answer to Question #272477 in Physics for JAY KIN

Question

A 5.0m long ladder who weighs 180N rests against a vertical wall, making an angle of 53 degrees with the ground. When a person who weighs 800N climbs this uniform ladder and stops one-third of the way up the ladder. Find the normal and frictional forces on the ladder at its base.

Answer 1

$\sum F_y=0:\ N_A=980\to N_A=980\ (N)$ . Answer

$\sum F_x=0:\ -N_B+F_{fr\ A}=0\to F_{fr\ A}=N_B$

$\sum M_A=0:\ 180\cdot1.5+800\cdot2-4N_B=0\to N_B=268\ (N)$

$F_{fr\ A}=N_B=268\ (N)$ . Answer