You turned the knob of a 194.22 cm by 103.86 cm door (with a mass of 9.05 kg) and pushed it with a perpendicular force of 5.18N to open it. What is the approximate torque on the door in (N⋅m)?
"\\tau=F\\cdot d=5.18\\cdot 1.0386=5.38\\ (N\\cdot m)" . Answer
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