Question

Three towns A, B, C are situated such that /AB/=25km and /AC/=30km. The bearing of B from A is 56°and bearing of C from A is 282°. Calculate the distance /BC/

Answer 1

$360°-282°=78°$

$78°+56°=134°$

$BC=\sqrt{25^2+30^2-2\cdot25\cdot30\cdot\cos134°}=50.7\ (km)$ . Answer