Answer to Question #270541 in Physics for Mitch

Question #270541

1. Determine thedisplacement of a periodic motion given that the time it takes to complete one cycle is 1 second and the amplitude is 1 meter (y=-3.071790 x 10-⁷ m)



2. What is the angular frequency of an oscillating device at a period of 150 ms? (w=2400°/sec or 41.8879 rad/sec)



3. A pendulum is observed to complete 20 full cycles in 58 seconds. Determine the frequency (f = 0.34 cycle/sec)



4. Determine the frequencies of the following periods


a. 30 seconds


b. 3 seconds


c. 30 ms


d. 3000 seconds

1
Expert's answer
2021-11-24T12:00:30-0500

1. The displacement in 1 s is


"y=A\\sin(\\omega t)=A\\sin\\bigg(\\frac{2\\pi}Tt\\bigg)=0."

2. We have


"\\omega=2\\pi\/T=41.89\\text{ rad\/s}."

3. The frequency is


"f=\\frac1T=\\frac Nt=0.34\\text{ Hz}."


4. The frequencies are


"f_a=\\frac 1{T_a}=0.033\\text{ Hz},\\\\\\space\\\\\nf_b=\\frac 1{T_b}=0.33\\text{ Hz},\\\\\\space\\\\\nf_c=\\frac 1{T_c}=33\\text{ Hz},\\\\\\space\\\\\nf_d=\\frac 1{T_d}=3.3\u00b710^{-4}\\text{ Hz}."


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

LATEST TUTORIALS
New on Blog