You have measure the length of a rope as 15.46 m, using a meter ruler. Find the present error associated with the measurement.
l=(15.460±0.005) m; ϵ=(0.005/15.460)⋅100 %=0.03 %l=(15.460\pm0.005)\ m; \ \epsilon=(0.005/15.460)\cdot100\ \%=0.03\ \%l=(15.460±0.005) m; ϵ=(0.005/15.460)⋅100 %=0.03 %
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