Answer to Question #270452 in Physics for FutureBSP

Question

A small stone is thrown away into the air with a velocity of 15 m/s at an angle of 30 degree along the horizontal. (With solution)

a. Find the maximum height reached by the object,

b. Time of flight, and

C. Range

Answer 1

a. The height:

$$h=\frac{v^2\sin^2\theta}{2g}=2.87\text{ m}.$$

b. Time of flight:

$$t=2\frac{v\sin\theta}{g}=1.53\text{ s}.$$

c. Range:

$$r=\frac{v^2\sin(2\theta)}{g}=19.9\text{ m}.$$