Answer to Question #270362 in Physics for Mish

Question

A car initially at rest accelerates at 5.22 M/S to the second for 14.9 seconds how far did it go in this time

Answer 1

We can find the distance traveled by the car as follows:

$$d=\dfrac{1}{2}at^2=\dfrac{1}{2}\times5.22\ \dfrac{m}{s^2}\times(14.9\ s)^2=579\ m.$$