estimate the hall voltages generated in each case across a 5mm width of sample of thickness 1mm when a current 100mA is passed along it and the perpendicular field is given as 100mT
Suppose the sample is made of copper
V=IB/(nde)=0.1⋅0.1/(8.4⋅1028⋅0.001⋅1.6⋅10−19)=V=IB/(nde)=0.1\cdot0.1/(8.4\cdot10^{28}\cdot0.001\cdot1.6\cdot10^{-19})=V=IB/(nde)=0.1⋅0.1/(8.4⋅1028⋅0.001⋅1.6⋅10−19)=
=7.4⋅10−10 (V)=7.4\cdot10^{-10}\ (V)=7.4⋅10−10 (V)
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