in a uniform electric field near the surface of earth, a particule having a charge of -2.0*10^-9C is acted on by a downward electric force of 3.0*10^-6N, what is the magnitude of the electric field
"F=qE\\to E=F\/q=3\\cdot10^{-6}\/(2\\cdot10^{-9})=1500\\ (V\/m)" . Answer
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