Question

in a uniform electric field near the surface of earth, a particule having a charge of -2.0*10^-9C is acted on by a downward electric force of 3.0*10^-6N, what is the magnitude of the electric field

Answer 1

$F=qE\to E=F/q=3\cdot10^{-6}/(2\cdot10^{-9})=1500\ (V/m)$ . Answer