an object 0.4 m from a lens gives a virtual image 0.1 m from the lens what is the focal length of this lens what kind of lens is this
1/a−1/b=1/f→1/f=1/0.4−1/0.1→f=−0.133 (m)1/a-1/b=1/f\to1/f=1/0.4-1/0.1\to f=-0.133\ (m)1/a−1/b=1/f→1/f=1/0.4−1/0.1→f=−0.133 (m)
Since the focal length is negative. It is a diverging lens.
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