Question #269497

A 3.56 kg block resting on a smooth horizontal surface is attached to a string that passes over a frictionless pulley as shown in the figure. The pulley has a radius of 0.28 m. A force of 7.5 N pulls the other end of the string. As a result, the block moves a distance of 0.2 m starting from rest. Find the (a) acceleration of the block, (b) angular acceleration of the pulley, and (c) moment of inertia of the pulley. 

1
Expert's answer
2021-11-21T17:31:34-0500

Assume that the moving time is 1.5 s.


(a) s=at2/2a=2s/t2=20.2/1.52=0.18 (m/s2)s=at^2/2\to a=2s/t^2=2\cdot0.2/1.5^2=0.18\ (m/s^2)


(b) ϵ=a/r=0.18/0.28=0.64 (rad/s2)\epsilon=a/r=0.18/0.28=0.64\ (rad/s^2)


(c) T=maT=ma

FrTr=Ia/rFr-Tr=Ia/r


Frmar=Ia/rI=r(Frmar)a=Fr-mar=Ia/r\to I=\frac{r(Fr-mar)}{a}=


=0.28(7.50.283.560.180.28)0.18=3 (kgm2)=\frac{0.28\cdot(7.5\cdot 0.28-3.56\cdot 0.18\cdot 0.28)}{0.18}=3\ (kg\cdot m^2)





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